There are two kangaroos on a number line ready to jump in the positive direction. Each kangaroo takes the same amount of time to make a jump, regardless of distance. That is, if kangaroo one jumps `3`

meters and kangaroo two jumps `5`

meters, they each do it in one second, for example.

Given the starting locations and jump distances for each kangaroo, determine if and when they will land at the same location at the same time.

**Input Format**

Parametes as integers denoting the respective values of `x1`

, `v1`

, `x2`

, and `v2`

.

**Constraints**

$$0 \le x1 \le x2 \le 10000$$ $$1 \le v1 \le 10000$$ $$1 \le v2 \le 10000$$

**Output Format**

Boolean value denoting if they can land on the same location at the same time.

**Sample Input**

```
x1 = 0
v1 = 3
x2 = 4
v2 = 2
```

**Sample Output**

```
true
```

**Explanation**

The two kangaroos jump through the following sequence of locations:

The kangaroos meet after 4 jumps.

**Solution**

This is a linear equation problem and we can represent them as:

$$ k1 = 3x + 0 $$

$$ k2 = 2x + 4 $$

Therefore:

$$3x = 2x + 4 $$

$$x = 4 $$

The kangaroos meet after 4 jumps. So the equation result must be a positive and whole number in order to fit the requirements.

**Code**

```
public class KangarooMeasurer {
private Boolean measure(
Integer x1,
Integer v1,
Integer x2,
Integer v2){
double left = v1 - v2;
double right = x2 - x1;
if(left < 0){
left = left * -1;
right = right * -1;
}
double result = right / left;
return right > 0 && result % 1 == 0;
}
public static void main(String[] args){
Integer x1 = 0;
Integer v1 = 3;
Integer x2 = 4;
Integer v2 = 2;
Boolean meets = new KangarooMeasurer().measure(x1, v1, x2, v2);
assert true == meets;
}
}
```

To Download the code:

```
git clone https://github.com/josdem/algorithms-workshop.git
cd kangaroo
```

To run the code:

```
javac KangarooMeasurer.java
java -ea KangarooMeasurer
```